3.160 \(\int \cos ^3(a+b x) \csc ^5(2 a+2 b x) \, dx\)
Optimal. Leaf size=70 \[ \frac{15 \sec (a+b x)}{256 b}-\frac{15 \tanh ^{-1}(\cos (a+b x))}{256 b}-\frac{\csc ^4(a+b x) \sec (a+b x)}{128 b}-\frac{5 \csc ^2(a+b x) \sec (a+b x)}{256 b} \]
[Out]
(-15*ArcTanh[Cos[a + b*x]])/(256*b) + (15*Sec[a + b*x])/(256*b) - (5*Csc[a + b*x]^2*Sec[a + b*x])/(256*b) - (C
sc[a + b*x]^4*Sec[a + b*x])/(128*b)
________________________________________________________________________________________
Rubi [A] time = 0.069867, antiderivative size = 70, normalized size of antiderivative = 1.,
number of steps used = 6, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used =
{4287, 2622, 288, 321, 207} \[ \frac{15 \sec (a+b x)}{256 b}-\frac{15 \tanh ^{-1}(\cos (a+b x))}{256 b}-\frac{\csc ^4(a+b x) \sec (a+b x)}{128 b}-\frac{5 \csc ^2(a+b x) \sec (a+b x)}{256 b} \]
Antiderivative was successfully verified.
[In]
Int[Cos[a + b*x]^3*Csc[2*a + 2*b*x]^5,x]
[Out]
(-15*ArcTanh[Cos[a + b*x]])/(256*b) + (15*Sec[a + b*x])/(256*b) - (5*Csc[a + b*x]^2*Sec[a + b*x])/(256*b) - (C
sc[a + b*x]^4*Sec[a + b*x])/(128*b)
Rule 4287
Int[(cos[(a_.) + (b_.)*(x_)]*(e_.))^(m_.)*sin[(c_.) + (d_.)*(x_)]^(p_.), x_Symbol] :> Dist[2^p/e^p, Int[(e*Cos
[a + b*x])^(m + p)*Sin[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && EqQ[b*c - a*d, 0] && EqQ[d/b, 2]
&& IntegerQ[p]
Rule 2622
Int[csc[(e_.) + (f_.)*(x_)]^(n_.)*((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Dist[1/(f*a^n), Subst[Int
[x^(m + n - 1)/(-1 + x^2/a^2)^((n + 1)/2), x], x, a*Sec[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n
+ 1)/2] && !(IntegerQ[(m + 1)/2] && LtQ[0, m, n])
Rule 288
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^
n)^(p + 1))/(b*n*(p + 1)), x] - Dist[(c^n*(m - n + 1))/(b*n*(p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x
], x] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] && !ILtQ[(m + n*(p + 1) + 1)/n, 0]
&& IntBinomialQ[a, b, c, n, m, p, x]
Rule 321
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]
Rule 207
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])
Rubi steps
\begin{align*} \int \cos ^3(a+b x) \csc ^5(2 a+2 b x) \, dx &=\frac{1}{32} \int \csc ^5(a+b x) \sec ^2(a+b x) \, dx\\ &=\frac{\operatorname{Subst}\left (\int \frac{x^6}{\left (-1+x^2\right )^3} \, dx,x,\sec (a+b x)\right )}{32 b}\\ &=-\frac{\csc ^4(a+b x) \sec (a+b x)}{128 b}+\frac{5 \operatorname{Subst}\left (\int \frac{x^4}{\left (-1+x^2\right )^2} \, dx,x,\sec (a+b x)\right )}{128 b}\\ &=-\frac{5 \csc ^2(a+b x) \sec (a+b x)}{256 b}-\frac{\csc ^4(a+b x) \sec (a+b x)}{128 b}+\frac{15 \operatorname{Subst}\left (\int \frac{x^2}{-1+x^2} \, dx,x,\sec (a+b x)\right )}{256 b}\\ &=\frac{15 \sec (a+b x)}{256 b}-\frac{5 \csc ^2(a+b x) \sec (a+b x)}{256 b}-\frac{\csc ^4(a+b x) \sec (a+b x)}{128 b}+\frac{15 \operatorname{Subst}\left (\int \frac{1}{-1+x^2} \, dx,x,\sec (a+b x)\right )}{256 b}\\ &=-\frac{15 \tanh ^{-1}(\cos (a+b x))}{256 b}+\frac{15 \sec (a+b x)}{256 b}-\frac{5 \csc ^2(a+b x) \sec (a+b x)}{256 b}-\frac{\csc ^4(a+b x) \sec (a+b x)}{128 b}\\ \end{align*}
Mathematica [B] time = 0.338197, size = 195, normalized size = 2.79 \[ -\frac{\csc ^4\left (\frac{1}{2} (a+b x)\right )}{2048 b}-\frac{7 \csc ^2\left (\frac{1}{2} (a+b x)\right )}{1024 b}+\frac{\sec ^4\left (\frac{1}{2} (a+b x)\right )}{2048 b}+\frac{7 \sec ^2\left (\frac{1}{2} (a+b x)\right )}{1024 b}+\frac{15 \log \left (\sin \left (\frac{1}{2} (a+b x)\right )\right )}{256 b}-\frac{15 \log \left (\cos \left (\frac{1}{2} (a+b x)\right )\right )}{256 b}+\frac{\sin \left (\frac{1}{2} (a+b x)\right )}{32 b \left (\cos \left (\frac{1}{2} (a+b x)\right )-\sin \left (\frac{1}{2} (a+b x)\right )\right )}-\frac{\sin \left (\frac{1}{2} (a+b x)\right )}{32 b \left (\sin \left (\frac{1}{2} (a+b x)\right )+\cos \left (\frac{1}{2} (a+b x)\right )\right )} \]
Antiderivative was successfully verified.
[In]
Integrate[Cos[a + b*x]^3*Csc[2*a + 2*b*x]^5,x]
[Out]
(-7*Csc[(a + b*x)/2]^2)/(1024*b) - Csc[(a + b*x)/2]^4/(2048*b) - (15*Log[Cos[(a + b*x)/2]])/(256*b) + (15*Log[
Sin[(a + b*x)/2]])/(256*b) + (7*Sec[(a + b*x)/2]^2)/(1024*b) + Sec[(a + b*x)/2]^4/(2048*b) + Sin[(a + b*x)/2]/
(32*b*(Cos[(a + b*x)/2] - Sin[(a + b*x)/2])) - Sin[(a + b*x)/2]/(32*b*(Cos[(a + b*x)/2] + Sin[(a + b*x)/2]))
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Maple [A] time = 0.03, size = 78, normalized size = 1.1 \begin{align*} -{\frac{1}{128\,b \left ( \sin \left ( bx+a \right ) \right ) ^{4}\cos \left ( bx+a \right ) }}-{\frac{5}{256\,b \left ( \sin \left ( bx+a \right ) \right ) ^{2}\cos \left ( bx+a \right ) }}+{\frac{15}{256\,b\cos \left ( bx+a \right ) }}+{\frac{15\,\ln \left ( \csc \left ( bx+a \right ) -\cot \left ( bx+a \right ) \right ) }{256\,b}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(cos(b*x+a)^3/sin(2*b*x+2*a)^5,x)
[Out]
-1/128/b/sin(b*x+a)^4/cos(b*x+a)-5/256/b/sin(b*x+a)^2/cos(b*x+a)+15/256/b/cos(b*x+a)+15/256/b*ln(csc(b*x+a)-co
t(b*x+a))
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Maxima [B] time = 1.49514, size = 3020, normalized size = 43.14 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(b*x+a)^3/sin(2*b*x+2*a)^5,x, algorithm="maxima")
[Out]
1/512*(4*(15*cos(9*b*x + 9*a) - 40*cos(7*b*x + 7*a) + 18*cos(5*b*x + 5*a) - 40*cos(3*b*x + 3*a) + 15*cos(b*x +
a))*cos(10*b*x + 10*a) - 60*(3*cos(8*b*x + 8*a) - 2*cos(6*b*x + 6*a) - 2*cos(4*b*x + 4*a) + 3*cos(2*b*x + 2*a
) - 1)*cos(9*b*x + 9*a) + 12*(40*cos(7*b*x + 7*a) - 18*cos(5*b*x + 5*a) + 40*cos(3*b*x + 3*a) - 15*cos(b*x + a
))*cos(8*b*x + 8*a) - 160*(2*cos(6*b*x + 6*a) + 2*cos(4*b*x + 4*a) - 3*cos(2*b*x + 2*a) + 1)*cos(7*b*x + 7*a)
+ 8*(18*cos(5*b*x + 5*a) - 40*cos(3*b*x + 3*a) + 15*cos(b*x + a))*cos(6*b*x + 6*a) + 72*(2*cos(4*b*x + 4*a) -
3*cos(2*b*x + 2*a) + 1)*cos(5*b*x + 5*a) - 40*(8*cos(3*b*x + 3*a) - 3*cos(b*x + a))*cos(4*b*x + 4*a) + 160*(3*
cos(2*b*x + 2*a) - 1)*cos(3*b*x + 3*a) - 180*cos(2*b*x + 2*a)*cos(b*x + a) + 15*(2*(3*cos(8*b*x + 8*a) - 2*cos
(6*b*x + 6*a) - 2*cos(4*b*x + 4*a) + 3*cos(2*b*x + 2*a) - 1)*cos(10*b*x + 10*a) - cos(10*b*x + 10*a)^2 + 6*(2*
cos(6*b*x + 6*a) + 2*cos(4*b*x + 4*a) - 3*cos(2*b*x + 2*a) + 1)*cos(8*b*x + 8*a) - 9*cos(8*b*x + 8*a)^2 - 4*(2
*cos(4*b*x + 4*a) - 3*cos(2*b*x + 2*a) + 1)*cos(6*b*x + 6*a) - 4*cos(6*b*x + 6*a)^2 + 4*(3*cos(2*b*x + 2*a) -
1)*cos(4*b*x + 4*a) - 4*cos(4*b*x + 4*a)^2 - 9*cos(2*b*x + 2*a)^2 + 2*(3*sin(8*b*x + 8*a) - 2*sin(6*b*x + 6*a)
- 2*sin(4*b*x + 4*a) + 3*sin(2*b*x + 2*a))*sin(10*b*x + 10*a) - sin(10*b*x + 10*a)^2 + 6*(2*sin(6*b*x + 6*a)
+ 2*sin(4*b*x + 4*a) - 3*sin(2*b*x + 2*a))*sin(8*b*x + 8*a) - 9*sin(8*b*x + 8*a)^2 - 4*(2*sin(4*b*x + 4*a) - 3
*sin(2*b*x + 2*a))*sin(6*b*x + 6*a) - 4*sin(6*b*x + 6*a)^2 - 4*sin(4*b*x + 4*a)^2 + 12*sin(4*b*x + 4*a)*sin(2*
b*x + 2*a) - 9*sin(2*b*x + 2*a)^2 + 6*cos(2*b*x + 2*a) - 1)*log(cos(b*x)^2 + 2*cos(b*x)*cos(a) + cos(a)^2 + si
n(b*x)^2 - 2*sin(b*x)*sin(a) + sin(a)^2) - 15*(2*(3*cos(8*b*x + 8*a) - 2*cos(6*b*x + 6*a) - 2*cos(4*b*x + 4*a)
+ 3*cos(2*b*x + 2*a) - 1)*cos(10*b*x + 10*a) - cos(10*b*x + 10*a)^2 + 6*(2*cos(6*b*x + 6*a) + 2*cos(4*b*x + 4
*a) - 3*cos(2*b*x + 2*a) + 1)*cos(8*b*x + 8*a) - 9*cos(8*b*x + 8*a)^2 - 4*(2*cos(4*b*x + 4*a) - 3*cos(2*b*x +
2*a) + 1)*cos(6*b*x + 6*a) - 4*cos(6*b*x + 6*a)^2 + 4*(3*cos(2*b*x + 2*a) - 1)*cos(4*b*x + 4*a) - 4*cos(4*b*x
+ 4*a)^2 - 9*cos(2*b*x + 2*a)^2 + 2*(3*sin(8*b*x + 8*a) - 2*sin(6*b*x + 6*a) - 2*sin(4*b*x + 4*a) + 3*sin(2*b*
x + 2*a))*sin(10*b*x + 10*a) - sin(10*b*x + 10*a)^2 + 6*(2*sin(6*b*x + 6*a) + 2*sin(4*b*x + 4*a) - 3*sin(2*b*x
+ 2*a))*sin(8*b*x + 8*a) - 9*sin(8*b*x + 8*a)^2 - 4*(2*sin(4*b*x + 4*a) - 3*sin(2*b*x + 2*a))*sin(6*b*x + 6*a
) - 4*sin(6*b*x + 6*a)^2 - 4*sin(4*b*x + 4*a)^2 + 12*sin(4*b*x + 4*a)*sin(2*b*x + 2*a) - 9*sin(2*b*x + 2*a)^2
+ 6*cos(2*b*x + 2*a) - 1)*log(cos(b*x)^2 - 2*cos(b*x)*cos(a) + cos(a)^2 + sin(b*x)^2 + 2*sin(b*x)*sin(a) + sin
(a)^2) + 4*(15*sin(9*b*x + 9*a) - 40*sin(7*b*x + 7*a) + 18*sin(5*b*x + 5*a) - 40*sin(3*b*x + 3*a) + 15*sin(b*x
+ a))*sin(10*b*x + 10*a) - 60*(3*sin(8*b*x + 8*a) - 2*sin(6*b*x + 6*a) - 2*sin(4*b*x + 4*a) + 3*sin(2*b*x + 2
*a))*sin(9*b*x + 9*a) + 12*(40*sin(7*b*x + 7*a) - 18*sin(5*b*x + 5*a) + 40*sin(3*b*x + 3*a) - 15*sin(b*x + a))
*sin(8*b*x + 8*a) - 160*(2*sin(6*b*x + 6*a) + 2*sin(4*b*x + 4*a) - 3*sin(2*b*x + 2*a))*sin(7*b*x + 7*a) + 8*(1
8*sin(5*b*x + 5*a) - 40*sin(3*b*x + 3*a) + 15*sin(b*x + a))*sin(6*b*x + 6*a) + 72*(2*sin(4*b*x + 4*a) - 3*sin(
2*b*x + 2*a))*sin(5*b*x + 5*a) - 40*(8*sin(3*b*x + 3*a) - 3*sin(b*x + a))*sin(4*b*x + 4*a) + 480*sin(3*b*x + 3
*a)*sin(2*b*x + 2*a) - 180*sin(2*b*x + 2*a)*sin(b*x + a) + 60*cos(b*x + a))/(b*cos(10*b*x + 10*a)^2 + 9*b*cos(
8*b*x + 8*a)^2 + 4*b*cos(6*b*x + 6*a)^2 + 4*b*cos(4*b*x + 4*a)^2 + 9*b*cos(2*b*x + 2*a)^2 + b*sin(10*b*x + 10*
a)^2 + 9*b*sin(8*b*x + 8*a)^2 + 4*b*sin(6*b*x + 6*a)^2 + 4*b*sin(4*b*x + 4*a)^2 - 12*b*sin(4*b*x + 4*a)*sin(2*
b*x + 2*a) + 9*b*sin(2*b*x + 2*a)^2 - 2*(3*b*cos(8*b*x + 8*a) - 2*b*cos(6*b*x + 6*a) - 2*b*cos(4*b*x + 4*a) +
3*b*cos(2*b*x + 2*a) - b)*cos(10*b*x + 10*a) - 6*(2*b*cos(6*b*x + 6*a) + 2*b*cos(4*b*x + 4*a) - 3*b*cos(2*b*x
+ 2*a) + b)*cos(8*b*x + 8*a) + 4*(2*b*cos(4*b*x + 4*a) - 3*b*cos(2*b*x + 2*a) + b)*cos(6*b*x + 6*a) - 4*(3*b*c
os(2*b*x + 2*a) - b)*cos(4*b*x + 4*a) - 6*b*cos(2*b*x + 2*a) - 2*(3*b*sin(8*b*x + 8*a) - 2*b*sin(6*b*x + 6*a)
- 2*b*sin(4*b*x + 4*a) + 3*b*sin(2*b*x + 2*a))*sin(10*b*x + 10*a) - 6*(2*b*sin(6*b*x + 6*a) + 2*b*sin(4*b*x +
4*a) - 3*b*sin(2*b*x + 2*a))*sin(8*b*x + 8*a) + 4*(2*b*sin(4*b*x + 4*a) - 3*b*sin(2*b*x + 2*a))*sin(6*b*x + 6*
a) + b)
________________________________________________________________________________________
Fricas [B] time = 0.506712, size = 375, normalized size = 5.36 \begin{align*} \frac{30 \, \cos \left (b x + a\right )^{4} - 50 \, \cos \left (b x + a\right )^{2} - 15 \,{\left (\cos \left (b x + a\right )^{5} - 2 \, \cos \left (b x + a\right )^{3} + \cos \left (b x + a\right )\right )} \log \left (\frac{1}{2} \, \cos \left (b x + a\right ) + \frac{1}{2}\right ) + 15 \,{\left (\cos \left (b x + a\right )^{5} - 2 \, \cos \left (b x + a\right )^{3} + \cos \left (b x + a\right )\right )} \log \left (-\frac{1}{2} \, \cos \left (b x + a\right ) + \frac{1}{2}\right ) + 16}{512 \,{\left (b \cos \left (b x + a\right )^{5} - 2 \, b \cos \left (b x + a\right )^{3} + b \cos \left (b x + a\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(b*x+a)^3/sin(2*b*x+2*a)^5,x, algorithm="fricas")
[Out]
1/512*(30*cos(b*x + a)^4 - 50*cos(b*x + a)^2 - 15*(cos(b*x + a)^5 - 2*cos(b*x + a)^3 + cos(b*x + a))*log(1/2*c
os(b*x + a) + 1/2) + 15*(cos(b*x + a)^5 - 2*cos(b*x + a)^3 + cos(b*x + a))*log(-1/2*cos(b*x + a) + 1/2) + 16)/
(b*cos(b*x + a)^5 - 2*b*cos(b*x + a)^3 + b*cos(b*x + a))
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(b*x+a)**3/sin(2*b*x+2*a)**5,x)
[Out]
Timed out
________________________________________________________________________________________
Giac [B] time = 1.3116, size = 220, normalized size = 3.14 \begin{align*} \frac{\frac{{\left (\frac{16 \,{\left (\cos \left (b x + a\right ) - 1\right )}}{\cos \left (b x + a\right ) + 1} - \frac{90 \,{\left (\cos \left (b x + a\right ) - 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{2}} - 1\right )}{\left (\cos \left (b x + a\right ) + 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) - 1\right )}^{2}} - \frac{16 \,{\left (\cos \left (b x + a\right ) - 1\right )}}{\cos \left (b x + a\right ) + 1} + \frac{{\left (\cos \left (b x + a\right ) - 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{2}} + \frac{128}{\frac{\cos \left (b x + a\right ) - 1}{\cos \left (b x + a\right ) + 1} + 1} + 60 \, \log \left (\frac{{\left | -\cos \left (b x + a\right ) + 1 \right |}}{{\left | \cos \left (b x + a\right ) + 1 \right |}}\right )}{2048 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(b*x+a)^3/sin(2*b*x+2*a)^5,x, algorithm="giac")
[Out]
1/2048*((16*(cos(b*x + a) - 1)/(cos(b*x + a) + 1) - 90*(cos(b*x + a) - 1)^2/(cos(b*x + a) + 1)^2 - 1)*(cos(b*x
+ a) + 1)^2/(cos(b*x + a) - 1)^2 - 16*(cos(b*x + a) - 1)/(cos(b*x + a) + 1) + (cos(b*x + a) - 1)^2/(cos(b*x +
a) + 1)^2 + 128/((cos(b*x + a) - 1)/(cos(b*x + a) + 1) + 1) + 60*log(abs(-cos(b*x + a) + 1)/abs(cos(b*x + a)
+ 1)))/b